if my calculations are correct.....

Posted:
in General Discussion edited January 2014
SLINKY + ESCULATOR = EVERLASTING FUN
«1

Comments

  • Reply 1 of 25
    jwri004jwri004 Posts: 626member
    Timing is everything.....
  • Reply 2 of 25
    the escalator would have to be moving at a pretty good clip...
  • Reply 3 of 25
    until the nasty horrible death when the slinky got jammed in the cracks in the escalator. Has anyone ever stretched a slingy out straight? How Long?
  • Reply 4 of 25
    scottscott Posts: 7,431member
    2*pi*r*L where r is the radius of the coil and L is the number of stacked coils.
  • Reply 5 of 25
    Quote:

    Originally posted by Scott

    2*pi*r*L where r is the radius of the coil and L is the number of stacked coils.



    That is clearly wrong, because you havn't allowed for the fact that each coil is not planar. Try again.
  • Reply 6 of 25
    scottscott Posts: 7,431member
    I'm sure it's close enough Calcualte how much extra lenght you'ld need of the offset were the width of the wire.
  • Reply 7 of 25
    wrong robotwrong robot Posts: 3,907member
    I like the concept, but I fear that the escalator would likely eat the slinky, unless you were superb with your slinky skills.



    didn't I already respond to this thread when it first dropped? guess not \



    Another thing I'd like to do is ride a wheeled something(bicycle, skateboard, scooter, unicycle) on one of those horizontal escalator dealies at airports.
  • Reply 8 of 25
    Quote:

    Originally posted by powermacG6

    That is clearly wrong, because you havn't allowed for the fact that each coil is not planar. Try again.



    Clearly there is also the issue that unless you are heating the coil it will never be straight...
  • Reply 9 of 25
    scottscott Posts: 7,431member
    Here's an alternative method.



    Determine the mass m. Determine the cross sectional area of the wire, A. Knowing the density p.



    L= m/Ap.



    QED
  • Reply 10 of 25
    Quote:

    Originally posted by Wrong Robot



    Another thing I'd like to do is ride a wheeled something(bicycle, skateboard, scooter, unicycle) on one of those horizontal escalator dealies at airports.




    Hmm. I want to do that too! Great idea.
  • Reply 11 of 25
    given small enough wheels you might be able to stay vertical if you peddled just enough to break friction.
  • Reply 12 of 25
    shetlineshetline Posts: 4,695member
    Quote:

    Originally posted by Wrong Robot

    Another thing I'd like to do is ride a wheeled something(bicycle, skateboard, scooter, unicycle) on one of those horizontal escalator dealies at airports.



    The problem is you'd be tackled, beaten, arrested as a terrorist, thrown in jail, and give a full body cavity search while your bicycle was being x-rayed then sliced into tiny pieces in a search for explosives.



    Not that there's anything particularly scary or threatening about a bicycle in an airport, but these guys just don't have much of a sense of humor anymore.
  • Reply 13 of 25
    Quote:

    Originally posted by Scott

    Here's an alternative method.



    Determine the mass m. Determine the cross sectional area of the wire, A. Knowing the density p.



    L= m/Ap.



    QED




    That is clearly wrong!



    You havn't allowed for the fact that density is dependant on temperature
  • Reply 14 of 25
    scottscott Posts: 7,431member
    Quote:

    Originally posted by powermacG6

    That is clearly wrong!



    You havn't allowed for the fact that density is dependant on temperature




    Trivial



    L(T)=m/A(T)p(T)



    QED
  • Reply 15 of 25
    what is the answer then?
  • Reply 16 of 25
    Quote:

    Originally posted by Scott

    Trivial



    L(T)=m/A(T)p(T)



    QED




    Heh. Assuming that the thermal expansion of the material is the same in all directions, A(T)= p(T) (V(T1)*A(T1)/m) where the V(T1) and A(T1) are the volume and cross sectional area of the slinky at a given temperature T1, respectively.



    This gives:



    L(T)= m^2/(p(T)^2 *(V(T1)*A(T1)))



    Of course this is assuming that the added mass energy from heating is negligible -- which as we know is an invalid assumption when discussing an infinitely long slinky, which we clearly are...
  • Reply 17 of 25
    Quote:

    Originally posted by powermacG6

    what is the answer then?



    A slinkyllion inches.
  • Reply 18 of 25
    scottscott Posts: 7,431member
    Infinitely long? We're trying to estimate the length of a manufactured slinky.



    Why don't we come to a consensus on the level of error we're willing to accept and that will help guide us on how complex our model needs to be? I think if we were within a centimeter that would be good.



    I'll contact the manufacture to see of we can get several hundred for destructive testing.
  • Reply 19 of 25
    I was joking -- all we need is the volume and the cross sectional area...
  • Reply 20 of 25
    about 63 feet.
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