Algebra problem that I need help with...
Hey guys, I was wondering if anyone could help me with this problem...I am taking an algebra class. Anyways, I would very much appreciate it if you could help me with it.
Two numbers have a ratio of 5:3. The larger number is 36 more than half the difference of the two numbers. What are the two numbers?
Note: There are two pairs of numbers that will make this a true statement. You need to find both of them.
<img src="confused.gif" border="0">
Two numbers have a ratio of 5:3. The larger number is 36 more than half the difference of the two numbers. What are the two numbers?
Note: There are two pairs of numbers that will make this a true statement. You need to find both of them.
<img src="confused.gif" border="0">
Comments
<strong>...
_You_ need to find both of them....</strong><hr></blockquote>
Hint ( If I understand your question ):
5x/3y = 36 + ( ( x - y )/2 )
5x/3y = 36 + ( ( y - x )/2 )
Solve for x and y.
<strong>Remember, guys. Don't give him the straight answer. You can help guide him, but don't cheat for him.</strong><hr></blockquote>
Ya, I hope I didn't come across like I was cheating. <img src="graemlins/oyvey.gif" border="0" alt="[No]" />
How would you set up such a problem? Is 5:3 the same as 5/3? Any help is much wanted.
a/b = 5/3
a = [1/2 * (a - b)] + 36
Solve these as well:
a/b = 5/3
a = [1/2 * (b - a)] + 36
[ 12-06-2002: Message edited by: Rick1138 ]</p>
<strong>
Hint ( If I understand your question ):
5x/3y = 36 + ( ( x - y )/2 )
5x/3y = 36 + ( ( y - x )/2 )
Solve for x and y.</strong><hr></blockquote>
LOL, you posted as I was posting...thanks...I'll see if it works.
<strong>Solve these two equations:
a/b = 5/3
a = [1/2 * (a - b)] + 36</strong><hr></blockquote>
LOL, posted while I was posting again. Thanks
I know mathematica exists... but that is some high end sh*t!
<strong>Solve these two equations:
a/b = 5/3
a = [1/2 * (a - b)] + 36
[ 12-06-2002: Message edited by: Rick1138 ]</strong><hr></blockquote>
I came up with this as well before I looked at anyone else's posts. That should give you one correct set of answers. I didn't get the other equations but after rereading the problem they look correct too. I must be a freak because I love algebra!
<strong>
Hint ( If I understand your question ):
5x/3y = 36 + ( ( x - y )/2 )
5x/3y = 36 + ( ( y - x )/2 )
Solve for x and y.</strong><hr></blockquote>
My approach agrees with Rick's. I'm not sure I understand what's going on in your equations?
P.S. Yes, a ratio of 5:3 is the same as saying 5/3.
[ 12-06-2002: Message edited by: frawgz ]</p>
=> difference is 2 units
Since difference between the 2 nos is 36, => 1 unit is 18
Now, solve it.
just to make sure u are on a right track, none of the nos are more than 100.
BTW, i hopw u are not a university student....
:eek:
To think I am a maths teacher....
rick's ans is correct.