What would you pay for a Quicksilver 867
It's not for sale yet, but I am having trouble justifying my Quicksilver now that I have a G4 iBook so I was wondering what you guys think it's worth/ would be willing to pay.
It's a Quicksilver 867 with 512Mb Ram and the 32meg Geforce 2Mx video card as well as a Rage 128 16meg PCI card allowing for up to 3 displays simultaneously (All together that's 1 ADC port, 1 DVI/VGA and 1 VGA.)
It's got a 5400 rpm 40 gig HD. I've added an extra 10/100 ethernet card and a Linksys 802.11g card which OSX recognizes as Airport Extreme. It was an education configuration and lacks L3 cache and a modem. It has an after-market Pioneer DVR-105 superdrive which works fine that I may or may not sell with it. (depending on if it ups the value enough) If not, I'll put the original Sony CD-RW drive back in it. It'll come with the white apple usb keyboard and the original black apple mouse as well as a set of Apple Pro speakers.
So how 'bout it, what would any interested parties be willing to pay for it with Superdrive or CD-RW?
It's a Quicksilver 867 with 512Mb Ram and the 32meg Geforce 2Mx video card as well as a Rage 128 16meg PCI card allowing for up to 3 displays simultaneously (All together that's 1 ADC port, 1 DVI/VGA and 1 VGA.)
It's got a 5400 rpm 40 gig HD. I've added an extra 10/100 ethernet card and a Linksys 802.11g card which OSX recognizes as Airport Extreme. It was an education configuration and lacks L3 cache and a modem. It has an after-market Pioneer DVR-105 superdrive which works fine that I may or may not sell with it. (depending on if it ups the value enough) If not, I'll put the original Sony CD-RW drive back in it. It'll come with the white apple usb keyboard and the original black apple mouse as well as a set of Apple Pro speakers.
So how 'bout it, what would any interested parties be willing to pay for it with Superdrive or CD-RW?
Comments
- Xidius
Honestly you are better off selling on eBay as people there pay too much for their systems.
There's probably a formula for this (MHz divided by years old, divided by 7?)